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@StudyCloud Elibrary Division
Published on Sept. 22nd 2021
Title : Std 7 Mathematics Chapter 15. Statistics
Maharashtra state board solutions for class 7 SSC board maths STD 7 Statistics
Know everything about Statistics Maharashtra state board class 7 SSC .Get detailed Questions and answers for chapter5 maths.
Important questions and answers
Average
Average means constituting the result obtained by adding together several amounts and then dividing this total by the number of amounts. The βaverageβ is a useful figure in the study of all branches of science including medicine, geography, economics, social science, etc.
For Example : The average of 10,20,30,40,50 will be :
ππ’π ππ πππ π πππππ ππ π‘βπ πππ£ππ πππ‘π = 10+20+30+40+50
πππ‘ππ ππ’ππππ ππ π πππππ 5
= 150
5
= 30
The samples that we have of the quantity we are measuring are called βreadingsβ or βscoresβ.
π΄π£πππππ = ππ’π ππ πππ π πππππ ππ π‘βπ πππ£ππ πππ‘π πππ‘ππ ππ’ππππ ππ π πππππ 2
*Q.1 Rutuja practised skipping with a rope all seven days of a week. The number of times she jumped the rope in one minute every day is given below. 60, 62, 61, 60, 59, 63, 58.
Solution : ππ’π ππ π‘βπ ππ’ππππ ππ ππ’πππ ππ π ππ£ππ πππ¦π
πππ‘ππ ππ’ππππ ππ πππ¦π
60 + 62 + 61 + 60 + 59 + 63 + 58
7
= 423
7
=60.42
Average number of jumps per minute = 60.42 We know that the number of jumps will be counted in natural numbers. Never will there be a fractional number of jumps. However, their average can be a fractional number.
Q.2 The annual rainfall of Mumbai is given below.
What is the average rainfall for those 5 years. 900mm,600mm,340mm,1000mm,850mm.
Solution : ππ’π ππ π‘βπ ππ’ππππ ππ ππ’πππ ππ π ππ£ππ πππ¦π
πππ‘ππ ππ’ππππ ππ πππ¦π
= 900 + 600 + 340 + 1000 + 850
5
3690
5
= 738
The average rainfall in Mumbai is 738mm.
π. Frequency Distribution Table
The number of times a particular score occurs in a data is called the 3 frequency of that score. In such cases a frequency table is made with three columns, one each for the score, the tally marks and the frequency.
1. In the first column, scores are entered in ascending order. For example, enter 1, 2, 3, 4, 5, 6 in order one below the other.
2. Read the scores in the data in serial order and enter a tally mark βΰ₯€β for each in the second column of the table in front of that score, e.g. if you read the score β3β, make a tally mark in front of 3 in the second column. Place four tally marks like this ΰ₯€ΰ₯€ΰ₯€ΰ₯€, but make the fifth one like this ΰ₯€ΰ₯€ΰ₯€ΰ₯€. It makes it easier to count the total number of tally marks.
3. Count the total number of tally marks in front of each score and enter the number in the next, i.e. third, column. This number is the frequency of the score.
4. Lastly, add all the frequencies. Their sum is denoted by the letter N. This sum is equal to the total number of scores.
A simple way to tabulate scores is by using tally marks. A table in which the number of tally marks indicates the frequency is called a frequency table. When the number of scores is very large, a frequency table is used to find their average.
Q.1 The marks of 20 students in Maths are given below.Prepare a frequency table. 10,12,10,12,15,15,12,14,18,12,13,16,19,13,19,20,18,19,17,20.
Solution
Marks(out of 20) | Tally Marks | Frequency 1 |
10 | II | 2 |
11 | - | - |
12 | IIII | 4 |
13 | II | 2 |
14 | I | 1 |
15 | II | 2 |
16 | I | 1 |
17 | I | 1 |
18 | II | 2 |
19 | III | 3 |
20 | II | 2 |
* Q.2. Priyaβs mother bought some peas and began to shell them. Priya was sitting nearby studying her maths lesson and she observed that some of the peapods had just 4 peas while some had 7. So, she took 50 of the pods and, as she shelled them, she noted down the number of peas in each of the pods. 4, 3, 2, 4, 3, 4, 3, 3, 2, 8 2, 3, 3, 4, 3, 4, 4, 5, 2, 8 8, 2, 5, 3, 4, 4, 3, 6, 2, 3 4, 4, 3, 3, 2, 6, 4, 4, 7, 2 3, 6, 3, 6, 6, 6, 7, 6, 7, 3
Prepare Frequency Table
Solution
Number of Peas in a pod | Tally Marks | Frequency |
2 | IIIIIIII | 8 |
3 | IIIIIIIIIIIIIII | 15 |
4 | IIIIIIIIIIII | 12 |
5 | II | 2 |
6 | IIIIIII | 7 |
7 | III | 3 |
8 | III | 3 |
Total frequency N=50 |
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